A) 0.3 eV
B) 1.3 eV
C) 2.3 eV
D) 5 eV
Correct Answer: C
Solution :
\[e\,{{V}_{sp}}\,=\,\frac{hc}{\lambda }\,\,-\,\,\phi \,\,\Rightarrow \,\,e{{V}_{sp}}\,+\,\phi \,\,=\,\,\frac{hc}{\lambda }\,\] \[1.3\,\,+\,\,\phi \,\,=\,\,\frac{hc}{4000}\] \[0.9\,\,+\,\,\phi \,\,=\,\,\frac{hc}{4500}\] \[\Rightarrow \,\,\,\frac{1.3+\phi }{0.9+\phi }\,\,=\,\,\frac{4500}{4000}\,\,=\,\,\frac{9}{8}\] \[10.4\,\,+\,\,8\phi \,\,=\,\,8.1\,\,+\,\,9\phi \] \[\Rightarrow \,\,\phi \,\,=\,\,2.3\text{ }eV\]You need to login to perform this action.
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