A) \[\frac{1}{4}\]
B) \[1\frac{1}{3}\]
C) 5
D) 4
Correct Answer: B
Solution :
\[{{T}_{1}}\,\,=\,\,2\,\,sec\] \[{{T}_{2}}\,\,=\,\,2\pi \,\sqrt{\frac{16}{g}}\] \[=\,\,4\,\left( 2\pi \sqrt{\frac{1}{g}} \right)\,\,=\,\,8\,\,\sec \] \[t\,\,=\,\,\frac{{{T}_{1}}{{T}_{2}}}{{{T}_{2}}-{{T}_{1}}}\,\,=\,\,\frac{(8)(2)}{8-2}\] \[t\,\,=\,\,\frac{8}{3}\] Number of oscillation of shorter pendulumYou need to login to perform this action.
You will be redirected in
3 sec