A) \[4450\,\Omega \]
B) \[5050\text{ }\Omega \]
C) \[5550\text{ }\Omega \]
D) \[6050\text{ }\Omega \]
Correct Answer: A
Solution :
\[{{I}_{g}}=\frac{3}{50+2950}\,\,=\,\frac{3}{3000}\] \[{{I}_{g}}\,\,=\,\,1\text{ }mA\] \[\because \,\,\,30\,\,\_\_\_\_\_\_\_\_\_\_\,\,=\,\,1\,\,mA\] \[\therefore \,\,\,1\,\,\_\_\_\_\_\_\_\_\_\_\,\,=\,\,\,\frac{1}{30}\] \[\therefore \,\,\,20\,\,\_\_\_\_\_\_\_\_\_\_\,\,=\,\,\,\frac{1}{30}\times 20\] \[\frac{2}{3}\,\,=\,\,\frac{3}{50+R}\]You need to login to perform this action.
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