A) 3.5N
B) 2.5N
C) 7N
D) 5N
Correct Answer: B
Solution :
[b] \[a=\frac{F}{m}=\frac{6}{7+5}=\frac{1}{2}m/{{s}^{2}}\] \[F-N=7a\] \[6-N=7\times \frac{1}{2}\] \[6-N=3.5\] \[N=2.5N\] Note: Normal force extorted by a body to another body in contactYou need to login to perform this action.
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