A) 1
B) 2
C) 4
D) 0.001
Correct Answer: D
Solution :
[d] 0.01 \[{{V}_{rms}}=\sqrt{\frac{3RT}{M}}\] \[\therefore {{\left( 30{{R}^{1/2}} \right)}^{2}}=\frac{3RT}{M}\] \[\Rightarrow 900R=\frac{3R\times 300}{M}\] \[or\,M=1g\,mo{{l}^{-1}}\] \[0.0001\,\,kg\,mo{{l}^{-1}}\]You need to login to perform this action.
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