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NEET Sample Paper NEET Sample Test Paper-56

  • question_answer
    A particle moves along the X-axis. The position x of a particle w.r.t. time from origin given by\[x={{b}_{\circ }}+{{b}_{1}}t+{{b}_{2}}{{t}^{2}}\]. The acceleration of the particle is:

    A) \[{{b}_{{}^\circ }}\]                            

    B) \[{{b}_{1}}\]   

    C) \[{{b}_{2}}\]                           

    D) \[2{{b}_{2}}\]

    Correct Answer: D

    Solution :

    [d] \[x={{b}_{0}}+{{b}_{1}}t+{{b}_{2}}{{t}^{2}}\] \[\frac{dx}{dt}=v={{b}_{1}}+2{{b}_{2}}t\] \[a=\frac{dv}{dt}=2{{b}_{2}}\]
    Note: \[v=\frac{dx}{dt}\] \[a=\frac{dv}{dt}\]


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