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NEET Sample Paper NEET Sample Test Paper-56

  • question_answer
    The temperature inside a refrigerator is \[{{t}_{2}}^{\circ }C\] and the room temperature is \[{{t}_{1}}^{\circ }C\] The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be:

    A) \[\frac{{{t}_{1}}+{{t}_{2}}}{{{t}_{1}}+273}\]                      

    B) \[\frac{{{t}_{1}}}{{{t}_{1}}+{{t}_{2}}}\]

    C) \[\frac{{{t}_{1}}+273}{{{t}_{1}}+{{t}_{2}}}\]                      

    D) \[\frac{{{t}_{2}}+273}{{{t}_{1}}+{{t}_{2}}}\]

    Correct Answer: D

    Solution :

    [d] Heat delivered =\[{{Q}_{1}}\] Coefficient of performance \[(\beta )=\frac{{{Q}_{2}}}{W}\] \[W={{Q}_{1}}-{{Q}_{2}}\] \[\beta =\frac{{{Q}_{2}}}{{{Q}_{1}}-{{Q}_{2}}}\] \[\frac{1}{\beta }=\frac{{{Q}_{1}}-{{Q}_{2}}}{{{Q}_{2}}}\] \[\frac{1}{{{Q}_{2}}}=\frac{{{t}_{1}}}{{{t}_{2}}}-1=\frac{{{t}_{1}}-{{t}_{2}}}{{{t}_{2}}}\therefore \frac{{{Q}_{1}}}{{{Q}_{2}}}=\frac{{{t}_{1}}}{{{t}_{2}}}\] \[{{Q}_{2}}=\frac{({{t}_{2}}+273)}{{{t}_{1}}-{{t}_{2}}}\]


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