A) No fringe would be seen
B) Fringe width would decrease
C) Fringe width would increase
D) Fringe width would remain unchanged
Correct Answer: B
Solution :
[b] \[\lambda \](wavelength) changes with medium Fringe width \[\beta =\frac{\lambda D}{d}\] \[{{\beta }_{1}}=\frac{\lambda }{\mu }\frac{D}{d}\] In new medium (Water) \[{{\lambda }_{1}}=\frac{{{\lambda }_{0}}}{\mu }\] \[{{\beta }_{1}}=\frac{\beta }{\mu }\]
You need to login to perform this action.
You will be redirected in
3 sec
