question_answer

Two block of masses 7kg and 5kg are placed in contact with each other on a smooth surface. If a force of 6N is applied on the heavier mass, the force on the lighter mass is:

A) 3.5N                

B) 2.5N   

C) 7N                   

D) 5N

Correct Answer: B

Solution :

[b] \[a=\frac{F}{m}=\frac{6}{7+5}=\frac{1}{2}m/{{s}^{2}}\] \[F-N=7a\] \[6-N=7\times \frac{1}{2}\] \[6-N=3.5\] \[N=2.5N\] Note: Normal force extorted by a body to another body in contact