A) \[C{{O}_{2}}<{{H}_{2}}{{O}_{2}}<{{H}_{2}}O\]
B) \[{{H}_{2}}O<{{H}_{2}}{{O}_{2}}<C{{O}_{2}}\]
C) \[{{H}_{2}}O<{{H}_{2}}{{O}_{2}}>C{{O}_{2}}\]
D) \[{{H}_{2}}{{O}_{2}}>C{{O}_{2}}>{{H}_{2}}O\]
Correct Answer: B
Solution :
[b] \[{{H}_{2}}O<{{H}_{2}}{{O}_{2}}<C{{O}_{2}}\] A stronger acid displaces a weaker acid from its salts \[Ba{{O}_{2}}+\underset{Stronger\,acid}{\mathop{{{H}_{2}}O+C{{O}_{2}}}}\,\,\to BaC{{O}_{3}}+\underset{Wea\ker \,acid}{\mathop{{{H}_{2}}{{O}_{2}}}}\,\] i.e. \[C{{O}_{2}}\]is stronger acid than \[{{H}_{2}}{{O}_{2}}\] .-. Hp < Hp, < CO,You need to login to perform this action.
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