A) \[100\,c{{m}^{3}}\]
B) \[450\,c{{m}^{3}}\]
C) \[500\,c{{m}^{3}}\]
D) \[400\text{ }c{{m}^{3}}\]
Correct Answer: D
Solution :
[d] \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[{{N}_{1}}=0.5N{{N}_{2}}0.1\] \[{{V}_{1}}=100c{{m}^{3}}\] \[0.5\times 100=0.1\times {{V}_{2}}\] \[\frac{0.5\times 100}{0.1}={{V}_{2}}\] \[{{V}_{2}}=500c{{m}^{3}}\]\[\therefore \,water\,to\,be\,added\,to\,100\,c{{m}^{3}}\,solution\] \[=500-100=400c{{m}^{3}}\]
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