A) \[sphybridised\]
B) \[s{{p}^{3}}dhybridised\]
C) \[s{{p}^{2}}hybridised\]
D) \[s{{p}^{3}}-ybridised\]
Correct Answer: A
Solution :
[a] sp-hybridised \[O=C=O\] Hence, \[C{{O}_{2}}\] is sp-hybridised
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