A) \[{{H}_{2}}O\]because of hydrogen bonding
B) \[{{H}_{2}}Te\]because of higher molecular weight
C) \[{{H}_{2}}S\]because of hydrogen boning
D) \[{{H}_{2}}Se\]because of lower molecular weight
Correct Answer: A
Solution :
[a] \[{{H}_{2}}O\]because of hydrogen bonding The compounds having hydrogen bonding show abnormally high melting and boiling points. \[{{H}_{2}}O\]is liquid whereas \[{{H}_{2}}S,\,{{H}_{2}}Se\]and \[{{H}_{2}}Te\] are all eases at ordinary temperature. The reason is that in case of\[{{H}_{2}}O\], hydrogen bonding causes association of \[{{H}_{2}}O\] molecules with the result that boiling point is more than that of other compounds.
You need to login to perform this action.
You will be redirected in
3 sec
