A) \[b=\frac{a}{2}\]
B) \[\operatorname{b} = a\]
C) \[\operatorname{b} = 2a\]
D) \[\operatorname{b} = 4a\]
Correct Answer: C
Solution :
[c] Initial velocity \[=\text{ }ai+b\hat{j}\] Range \[=2{{H}_{\max }}\] \[{{u}_{x}}a\,\,\,,\,\,\,{{u}_{y}}=b\] \[T=\frac{2{{u}_{y}}}{g}=\frac{2b}{g}\] \[H=\frac{u\,_{y}^{2}}{g}=\frac{2b}{g}\] \[R=\frac{2{{u}_{x}}{{u}_{y}}}{g}=\frac{2ab}{g}\] \[R\text{ }=\text{ }2H\] (given) \[2ab\,=\frac{2{{b}^{2}}}{2b}\] \[b=2a\]You need to login to perform this action.
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