A) \[\frac{GMm}{12R}\]
B) \[\frac{GMm}{R}\]
C) \[\frac{GMm}{8R}\]
D) \[\frac{GMm}{2R}\]
Correct Answer: A
Solution :
[a]\[KE=\frac{1}{2}\frac{mGM}{R}PE=-\frac{GMm}{R}\] \[TE=\frac{GMm}{2R}-\frac{GMm}{R}=-\frac{GMm}{2R}\] |
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