A) \[{{d}^{4}}\,(low\,spin)\]
B) \[{{d}^{8}}\,(high\,spin)\]
C) \[{{d}^{6}}\,(low\,spin)\]
D) \[~All\text{ }of\text{ }these\]
Correct Answer: C
Solution :
[c] \[{{d}^{6}}\](low spin) In \[{{d}^{6}}\](low spin), electron pair up thereby making two empty d-orbitals available for \[{{d}^{2}}S{{p}^{3}}\]hybridisation.
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