A) \[\frac{3v}{\sqrt{2}}\]
B) \[\frac{\sqrt{3v}}{2}\]
C) \[\frac{\sqrt{gH}}{2}\]
D) \[\frac{\sqrt{2g}}{H}\]
Correct Answer: C
Solution :
[c] \[g''=\frac{GM}{{{R}^{2}}}\left[ 1-\frac{d}{R} \right]=g\left[ 1-\frac{d}{R} \right]\] \[g'=0\,at\,d=R\] Acceleration due to gravity is zero at earth centre \[For\,r>Rg'\propto \frac{1}{{{r}^{2}}}\] \[For\,r>Rg'=g\left[ 1-\frac{d}{R} \right]=\frac{gr}{R}\] \[g'\propto r\]You need to login to perform this action.
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