A) h = R
B) h = 4R
C) h = 2R
D) h = 16R
Correct Answer: C
Solution :
[c] Acceleration due to gravity \[g\propto \frac{1}{{{R}^{2}}}\] \[g=\frac{K}{{{R}^{2}}}.......(1)\] When \[g''=\frac{g}{4}\]at another place which 'h' km from earth surface \[g''=\frac{K}{{{(R+h)}^{2}}}\] \[g''=\frac{K}{{{(R+h)}^{2}}}........(2)\] From 1 & 2 \[4={{\left[ \frac{R+h}{R} \right]}^{2}}\] \[\frac{R+h}{R}=2\] \[R+h=2R\] \[h=R\]
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