A) 0.5
B) 49
C) 98
D) 490
Correct Answer: B
Solution :
[b] By Newton's second law of motion \[\overrightarrow{F}{{ & }_{net}}=\frac{dp}{dt}\] Change in momentum = Impulse \[\overrightarrow{F}{{ & }_{net}}=dt\] \[=mg\times time\] \[=0.5\times 9.8\times 10\] \[=49\text{ }N-s\]You need to login to perform this action.
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