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NEET Sample Paper NEET Sample Test Paper-57

  • question_answer
    If acceleration of a particle at any time is given by a = 2t + 5 calculate the velocity after 5sec, if it starts from rest:

    A) 50m/s                           

    B) 25m/s

    C) 100m/s                         

    D) 75m/s

    Correct Answer: A

    Solution :

    [a] \[a=2t+5\] \[a=\frac{dv}{dt}=2t+5\] \[dv=2t\,dt+5dt\] Intergrate \[\int\limits_{{}^\circ }^{V}{dv}=\int\limits_{{}^\circ }^{5}{2t}\,dt\,+\int\limits_{{}^\circ }^{5}{5dt}\] \[v-o=\frac{2\,[{{t}^{2}}]_{{}^\circ }^{5}}{2}+5[t]_{{}^\circ }^{5}\] \[v=(25-0)+5\,[5-0]\] \[v=50m/s\]


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