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NEET Sample Paper NEET Sample Test Paper-57

  • question_answer
    In the Young's double slit experiment. The intensity of light at a point on the screen (where path difference is\[\lambda \]) is K, (\[\lambda \] being the wavelength used). The intensity at a point where the path difference is \[\lambda /4\], will be:

    A) \[K\]                                         

    B) \[\frac{K}{4}\]

    C) \[\frac{K}{2}\]                          

    D) \[Zero\]

    Correct Answer: C

    Solution :

    [c] Place where \[\Delta x=\lambda \] intensity \[=\text{ }K={{I}_{{}^\circ }}\] When \[\Delta \phi =\frac{2\pi }{\lambda }.\Delta x\] \[=\frac{2\pi }{\lambda }\frac{\lambda }{4}\] \[\frac{\pi }{2}\] Intensity \[{{I}_{{}^\circ }}\text{ }Cos{{\left[ \frac{\Delta \phi }{2} \right]}^{2}}\] \[{{I}_{{}^\circ }}\text{ }Cos{{\left[ \frac{90}{2} \right]}^{2}}=\frac{K}{2}\]


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