A) 2.28 mol/kg
B) 0.44 mol/kg
C) 1.14 mol/kg
D) 3.25 mol/kg
Correct Answer: A
Solution :
[a] \[2.28\text{ }mol\text{ }K{{g}^{-1}}\] Mass of 1L of solution \[=1.02\times 1000=1020g\] Mass of 2.05 moles of acetic acid \[=2.05\times 60=123g\] Mass of water \[=1020123\] \[=897g\] \[=0.897kg\] Thus, molality of the solution \[=\frac{2.05mol}{0.597kg}=2.285\,mol/kg\]You need to login to perform this action.
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