A) Order of their acidity is \[{{H}_{3}}P{{O}_{4}}>{{H}_{3}}PO>{{H}_{3}}P{{O}_{3}}>{{H}_{3}}P{{O}_{2}}\]
B) All are reducing in nature
C) All are tribasic acids
D) The geometry of phosphorus is tetrahedral in all the three
Correct Answer: A
Solution :
[a] Acidity order \[{{H}_{3}}P{{O}_{4}}>{{H}_{3}}P{{O}_{3}}>{{H}_{3}}P{{O}_{2}}\] \[{{H}_{3}}P{{O}_{2}}\]is a good reducing agent. \[{{H}_{3}}P{{O}_{2}}\] is dibasic (O.S +3) \[{{H}_{3}}P{{O}_{2}}\]is monobasic (O.S +1) \[{{H}_{3}}P{{O}_{4}}\] is tribasic (O.S +5). It is oxoacid. Higher the oxidation state (O.S), higher will be the acidity.You need to login to perform this action.
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