question_answer

A 50Hz AC source of 20V is connected across R and C as shown in figure. The voltage across R is 12V the voltage across C is:

A) 8V                               

B) 16V    

C) 10V                             

D) 20V

Correct Answer: B

Solution :

[b] \[{{V}^{2}}=V_{R}^{2}+V_{C}^{2}\] \[{{(20)}^{2}}={{(12)}^{2}}+V_{C}^{2}\] \[V_{C}^{2}=400-144=256\] \[V_{C}^{{}}=16V\]