A) \[6.023\times {{10}^{19}}\]
B) \[1.084\times {{10}^{18}}\,\]
C) \[\,4.84\times {{10}^{17}}\]
D) \[6.023\times {{10}^{23}}\]
Correct Answer: A
Solution :
[a] \[6.023\times {{10}^{19}}\] \[0.0018ml\,{{H}_{2}}O=0.0018\,g\,{{H}_{2}}O\] \[(\because density=1g/ml)\] \[1\,mol\,{{H}_{2}}O=18g\] =\[6.023\times {{10}^{19}}\]molecules
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