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NEET Sample Paper NEET Sample Test Paper-57

  • question_answer
    The orbital angular momentum of an electron in 2s orbital is:

    A) \[+\frac{1}{2}\frac{h}{2\pi }\]              

    B) \[Zero\]

    C) \[\frac{h}{2\pi }\]                                  

    D) \[Three\]

    Correct Answer: B

    Solution :

    [b] Zero Orbital angular momentum \[=\sqrt{1(1+1)}\frac{h}{2\pi }\] \[\therefore \] For 2s orbital, \[l=0\] Therefore Capital angular momentum \[=\sqrt{0(0+1)}\frac{h}{2\pi }=\frac{0h}{2\pi }=0\]


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