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NEET Sample Paper NEET Sample Test Paper-57

  • question_answer
    The decreasing valves of bond angles from \[N{{H}_{3}}\]\[({{106}^{{}^\circ }})\] to \[sb{{H}_{3}}({{101}^{{}^\circ }})\] down group-15 of the periodic table is due to:

    A) Decreasing Ip-bp repulsion

    B) Decreasing electronegativity

    C) Increasing Ip-bp repulsion

    D) Increasing p-orbital character in \[S{{p}^{3}}\]

    Correct Answer: B

    Solution :

    [b] Decreasing electronegativity Decreasing values of bond angles from \[N{{H}_{3}}({{106}^{{}^\circ }})\]to\[Sb{{H}_{3}}{{(101)}^{{}^\circ }}\]increases the electronegativity. Then bond pairs move farther and farther away from the central atom. As a result, bp-bp repulsion decreases and the angle decreases accordingly.


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