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NEET Sample Paper NEET Sample Test Paper-57

  • question_answer
    Density of a 2.05 M solution of acetic acid in water is 1.02 g/ml. The molality of the solution is:

    A) 2.28 mol/kg       

    B) 0.44 mol/kg

    C) 1.14 mol/kg       

    D) 3.25 mol/kg

    Correct Answer: A

    Solution :

    [a] \[2.28\text{ }mol\text{ }K{{g}^{-1}}\] Mass of 1L of solution \[=1.02\times 1000=1020g\] Mass of 2.05 moles of acetic acid \[=2.05\times 60=123g\] Mass of water \[=1020123\]                                     \[=897g\]                                     \[=0.897kg\] Thus, molality of the solution \[=\frac{2.05mol}{0.597kg}=2.285\,mol/kg\]


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