A) 2/3 mole of \[MnO_{4}^{-}\]and 1/3 mole of \[Mn{{O}_{2}}\]
B) 1/3 mole of \[MnO_{4}^{-}\] and 2/3 mole of \[Mn{{O}_{2}}\]
C) 1/3 mole of \[M{{n}_{2}}{{O}_{7}}\] and 1/3 mole of \[Mn{{O}_{2}}\]
D) 2/3 mole of \[M{{n}_{2}}{{O}_{7}}\] and 1/3 mole of \[Mn{{O}_{2}}\]
Correct Answer: A
Solution :
[a] \[\frac{2}{3}\] mole of \[MnO_{4}^{-}\]and \[\frac{1}{3}\]mole of \[Mn{{O}_{2}}\] \[3MnO_{4}^{2-}+2{{H}_{2}}O\to 2MnO_{4}^{2-}+Mn{{O}_{2}}+4OH\]
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