A) \[{{C}_{2}}{{H}_{5}}N{{H}_{2}}\]
B) \[C{{H}_{3}}N{{H}_{2}}\]
C) \[{{(C{{H}_{3}})}_{2}}CH-N{{H}_{2}}\]
D) \[All\,will\,give\,{{N}_{2}}\]
Correct Answer: D
Solution :
[d] All will give \[{{N}_{2}}\] \[{{C}_{2}}{{H}_{5}}N{{H}_{2}}+NaN{{O}_{2}}+HCl\] \[{{C}_{2}}{{H}_{3}}OH+{{N}_{2}}+NaCl+{{H}_{2}}O\] \[C{{H}_{3}}\,N{{H}_{2}}+NaN{{O}_{2}}+HCl\to \] \[C{{H}_{3}}OH+{{N}_{2}}+NaCl+{{H}_{2}}O\] \[(C{{H}_{3}})\ CH-N{{H}_{2}}+NaN{{O}_{2}}+HCl\to \] \[(C{{H}_{3}})\,CHOH+{{N}_{2}}+NaCl+{{H}_{2}}O\] All will give \[{{N}_{2}}\]
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