A) \[V_{1}^{2}-V_{2}^{2}=\frac{2h}{m}({{f}_{1}}-{{f}_{2}})\]
B) \[{{V}_{1}}-{{V}_{2}}=\sqrt{\frac{2h}{m}({{f}_{1}}-{{f}_{2}})}\]
C) \[V_{1}^{2}+V_{2}^{2}=\frac{2h}{m}({{f}_{1}}-{{f}_{2}})\]
D) \[{{V}_{1}}={{V}_{2}}\]
Correct Answer: A
Solution :
[a] Apply equation for photoelectric effect \[Case-1h{{f}_{1}}-{{W}_{{}^\circ }}+\frac{1}{2}mv_{1}^{2}.....(1)\] \[Case-2h{{f}_{2}}-{{W}_{{}^\circ }}+\frac{1}{2}mv_{2}^{2}.....(2)\] \[(1)-(2)\] \[h({{f}_{1}}-{{f}_{2}})=\frac{m}{2}[v_{1}^{2}-v_{2}^{2}]\] \[v_{1}^{2}-v_{2}^{2}\frac{2h}{m}[{{f}_{1}}-{{f}_{2}}]\]
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