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NEET Sample Paper NEET Sample Test Paper-58

  • question_answer
    The depth at which the value of acceleration due to gravity becomes \[\frac{1}{n}\] time the value at the surface is:

    A) \[\frac{R}{n}\]                          

    B) \[\frac{R(n-1)}{n}\]

    C) \[\frac{Rn}{(n-1)}\]                    

    D) \[\frac{R}{{{n}^{2}}}\]

    Correct Answer: B

    Solution :

    [b] \[g''=g\left[ 1-\frac{d}{R} \right]\] \[g''={}^{g}/{}_{n}\] \[\frac{g}{n}=g\,\left[ 1-\frac{d}{R} \right]\] \[\frac{1}{n}=\frac{1-d}{R}\] \[\frac{d}{R}=1-\frac{1}{n}=\frac{n-1}{n}\] \[d=\frac{R\,[n-1]}{n}\]


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