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NEET Sample Paper NEET Sample Test Paper-58

  • question_answer
    The current in a self-inductance L = 40mH is to be increased uniformly from 1A to 11A in 4ms. The emf induced in the inductor during the process is:

    A) 100V                            

    B) 0.4V   

    C) 40V                             

    D) 440V

    Correct Answer: A

    Solution :

    [a] \[e=-\frac{Ldi}{dt}\] \[e=\frac{-\,4\times {{10}^{-3}}\times [11-1]}{4\times {{10}^{-3}}}=100V\]


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