A) \[3.3\mu s\]
B) \[5.7\mu s\]
C) \[6.6\mu s\]
D) \[3.85\mu s\]
Correct Answer: D
Solution :
[d] When TIR just takes place from lateral surface \[i=C(C={{60}^{{}^\circ }})\] \[\frac{1}{\mu }=\sin \,{{60}^{{}^\circ }}\,\left[ Sin\,C=\frac{1}{\mu } \right]\] \[\mu =\frac{2}{\sqrt{3}}\] Time taken by light to traverse some distance \[t=\frac{\mu x}{C}=\frac{\frac{2}{\sqrt{3}}{{.10}^{3}}}{3\times {{10}^{8}}}\] \[t=3.85\mu s\]
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