A) \[\frac{C{{V}^{2}}}{4}\]
B) \[\frac{C{{V}^{2}}}{2}\]
C) \[\frac{3C{{V}^{2}}}{4}\]
D) \[C{{V}^{2}}\]
Correct Answer: D
Solution :
[b] \[C=\frac{A{{\varepsilon }_{{}^\circ }}}{d}\] \[Q=CV=\frac{A{{\varepsilon }_{{}^\circ }}}{d}V\] Battery remains connected implies that ?V? remains constant now distance between plates reduced to half \[C=\frac{A{{\varepsilon }_{{}^\circ }}}{{}^{d}/{}_{2}}=\frac{2a{{\varepsilon }_{{}^\circ }}}{d}\] \[{{E}_{2}}=\frac{1}{2}C{{V}^{2}}=\frac{1}{2}\times \frac{2a{{\varepsilon }_{{}^\circ }}}{d}{{V}^{2}}\] \[{{E}_{2}}=\frac{1}{2}C{{V}^{2}}\]
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