A) 0.15 mol/L
B) 0.30 mol/L
C) 0.60 mol/L
D) 0.45 mol/L
Correct Answer: A
Solution :
[a] 0.15 mol/L NaCI solution used should be isotonic with bloodstream. For NaCI \[i=2,\,\pi =iCRT\] \[\therefore \,\,C=\frac{\pi }{iRT}\] \[=\frac{7.8\,bar}{2\times 0.083\,bar\,L{{K}^{-1}}\,mo{{l}^{-1}}\times 310K}\]You need to login to perform this action.
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