A) \[\frac{{{L}^{2}}\rho g}{Y}\]
B) \[\frac{{{L}^{2}}\rho g}{2Y}\]
C) \[\frac{{{L}^{2}}\rho g}{4Y}\]
D) \[\frac{Y}{{{L}^{2}}\rho g}\]
Correct Answer: B
Solution :
[b] \[Y=\frac{FL}{A\,\Delta \ell }\] \[Y=\frac{mg}{2}\frac{L}{A\,\Delta \ell }m=V\ell \] \[Y=\frac{AL}{2A}\frac{\ell Lg}{\Delta \ell }m=AL\ell \] \[\Delta \ell =\frac{g{{L}^{2}}\ell }{zY}\]You need to login to perform this action.
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