A) \[\frac{R}{n}\]
B) \[\frac{R(n-1)}{n}\]
C) \[\frac{Rn}{(n-1)}\]
D) \[\frac{R}{{{n}^{2}}}\]
Correct Answer: B
Solution :
[b] \[g''=g\left[ 1-\frac{d}{R} \right]\] \[g''={}^{g}/{}_{n}\] \[\frac{g}{n}=g\,\left[ 1-\frac{d}{R} \right]\] \[\frac{1}{n}=\frac{1-d}{R}\] \[\frac{d}{R}=1-\frac{1}{n}=\frac{n-1}{n}\] \[d=\frac{R\,[n-1]}{n}\]You need to login to perform this action.
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