A) \[\theta ={{\tan }^{-1}}\mu \]
B) \[\theta ={{\tan }^{-1}}\frac{1}{\mu }\]
C) \[\theta ={{\tan }^{-1}}\frac{m}{\mu }\]
D) \[\theta ={{\tan }^{-1}}\frac{\mu }{m}\]
Correct Answer: B
Solution :
[a] At equilibrium \[mg\sin \,\theta =\mu \,\,mg\cos \theta \] \[\mu \,\,\tan \theta \] \[\theta \,{{\tan }^{-1}}(\mu )\]You need to login to perform this action.
You will be redirected in
3 sec