A) 1/2
B) 3/2
C) 5/2
D) 7/2
Correct Answer: C
Solution :
[c] J When \[KMn{{O}_{4}}\]reacts with\[{{H}_{2}}{{O}_{2}}\] the reaction is: in presence of \[{{H}_{2}}S{{O}_{4}}\] \[2KMn\,{{O}_{4}}+5{{H}_{2}}{{O}_{2}}+3{{H}_{2}}S{{O}_{4}}\] \[\to {{K}_{2}}S\,{{O}_{4}}+2MnS{{O}_{4}}+8{{H}_{2}}S{{O}_{4}}\] Since 2 moles of \[MnS{{O}_{4}}\] requires = 5 moles of \[{{H}_{2}}{{O}_{2}}\] 1 mole require moles of \[{{H}_{2}}{{O}_{2}}\] or = 2.5 molesYou need to login to perform this action.
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