A) \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\]
B) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}}\]
C) \[C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}\]
D) \[C{{H}_{3}}C{{H}_{2}}NHC{{H}_{3}}\]
Correct Answer: A
Solution :
[a] \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\] \[C{{H}_{3}}\,\underset{(A)}{\mathop{C{{H}_{2}}}}\,\,COOH\xrightarrow{SOC{{l}_{2}}}\,C{{H}_{3}}\,\underset{(B)}{\mathop{C{{H}_{2}}}}\,\,COCl\] \[\xrightarrow[-N{{H}_{4}}Cl]{N{{H}_{3}}(excess)}C{{H}_{3}}\,\underset{(c)}{\mathop{C{{H}_{2}}}}\,\,CN{{H}_{2}}\] \[\xrightarrow[{}]{B{{r}_{2}}/KOH}C{{H}_{3}}\,\underset{(D)}{\mathop{C{{H}_{2}}}}\,\,N{{H}_{2}}\]You need to login to perform this action.
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