question_answer

In which of the following molecular / ions are all the bonds not equal?

A) \[Xe{{F}_{4}}\]                        

B) \[BF_{4}^{-}\]    

C) \[SF_{4}^{{}}\]                      

D) \[SiF_{4}^{{}}\]

Correct Answer: C

Solution :

[c] \[S{{F}_{4}}\] \[Xe{{F}_{4}}\]is squar planar while \[BF_{4}^{-}\]and are\[Si{{F}_{4}}\] tetrahedral, all M-F bonds are equal in these molecules. However, in \[S{{F}_{4}}\] there is \[s{{p}^{3}}\]d-hybridisation having two axial and two equatorial S-F bonds. Thus, all the bonds in \[S{{F}_{4}}\] are not equal. Lone pair occupying axial position.