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NEET Sample Paper NEET Sample Test Paper-58

  • question_answer
    A proton accelerated through a potential V has de-broglie wave length\[\lambda \]. Then, broglie wavelength of an \[\alpha \]-particle accelerated through the same potent V:

    A) \[\frac{\lambda }{2}\]                            

    B) \[\frac{\lambda }{\sqrt{2}}\]

    C) \[\frac{\lambda }{2\sqrt{2}}\]                

    D) \[\frac{\lambda }{4}\]

    Correct Answer: C

    Solution :

    [c] \[\lambda =\frac{h}{\sqrt{2me\,V}}\] \[{{\lambda }^{2}}=\frac{{{h}^{2}}}{2{{m}_{p}}eV}........(1)\] \[\lambda _{\alpha }^{2}=\frac{h}{2(4{{m}_{p}})\,(2e)\,V}........(2)\] \[\therefore \,{{m}_{\alpha }}=4{{m}_{p}},{{e}_{\alpha }}=2{{e}_{p}}\] \[{{\lambda }_{\alpha }}=\frac{\lambda }{2\sqrt{2}}\]


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