A) 4
B) 1
C) 2
D) 3
Correct Answer: C
Solution :
[c] Wavelength of the first line of lyman series for hydrogen atom is (Z=1) \[\frac{1}{\lambda }=R\left[ \frac{1}{{{(1)}^{2}}}-\frac{1}{{{(2)}^{2}}} \right]=\frac{3R{{Z}^{2}}}{16}\Rightarrow {{\lambda }^{''}}=\frac{16}{3R{{Z}^{2}}}\] \[\lambda ''=\lambda \] \[\frac{16}{3R{{Z}^{2}}}=\frac{4}{3R}\Rightarrow Z=2\] Note In such question, sometimes we have use term \[\frac{1}{R}=911\,\overset{o}{\mathop{A}}\,\]You need to login to perform this action.
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