A) \[\frac{3\tan \,\theta }{4}\]
B) \[\frac{2\tan \,\theta }{3}\]
C) \[\frac{\tan \,\theta }{4}\]
D) \[\frac{\tan \,\theta }{2}\]
Correct Answer: A
Solution :
[a] \[a=g\,Sin\,\theta \] \[{{S}_{1}}=\frac{1}{2}g\,Sin\,\theta {{t}^{2}}\] \[{{S}_{2}}=\frac{1}{2}g\,[Sin\,\theta -\mu \,Cos\theta ]\,(2{{t}^{2}})\] \[\frac{1}{2}g\,Sin\,\theta {{t}^{2}}=\frac{1}{2}g\,[Sin\,\theta -\mu Cos\theta ]\,4{{t}^{2}}\] \[Sin\,\theta =4\,Sin\,\theta -4\mu \,Cos\theta \] \[4\mu \,Cos\theta =3\,Sin\theta \] \[\mu \,=\frac{3}{4}\tan \theta \]You need to login to perform this action.
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