A) ? 2pE
B) ? pE
C) pE
D) 2Pe
Correct Answer: D
Solution :
[d] \[{{\theta }_{1}}=0\][Initially dipole sets parallel to electric field] \[{{\theta }_{2}}=180{}^\circ \] \[Work\,done\,=PE\,[cos{{\theta }_{1}}-Cos{{\theta }_{2}}]\] \[\,=PE\,[cos0{}^\circ -Cos180{}^\circ ]\] \[\,=PE\,[1-(-1)]\] \[W=2PE\]You need to login to perform this action.
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