A) \[NO\]
B) \[CO\]
C) \[C{{N}^{-}}\]
D) \[{{O}_{2}}\]
Correct Answer: A
Solution :
[a] NO As only NO has odd number of electrons. (7 + 8 = 15) \[C{{N}^{-}}\]has 14 electrons i.e. 6 (from C) + 7(from N) +1 (due to negative charge) CO has 14 electrons 6[c] + 8(0) \[{{O}_{2}}\] has16 electrons 2x+8 (0)You need to login to perform this action.
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