A) 0.186
B) 0.512
C) 0.86
D) 0.0512
Correct Answer: D
Solution :
[d] 0.0512 For the depression in freezing point \[\Delta {{T}_{f}}={{k}_{f}}\times m\] Where \[{{k}_{f}}\] is a constant known as molal depression constant. \[\Delta {{T}_{b}}={{k}_{b}}\times m\] (for boiling point elevation) Hence, \[\frac{\Delta {{T}_{b}}}{0.186}=\frac{0.512}{1.86}\] \[\Delta {{T}_{b}}=0.0512{}^\circ C\]You need to login to perform this action.
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