A) \[2\pi \sqrt{\frac{m}{2K}}\]
B) \[2\pi \sqrt{\frac{2m}{2K}}\]
C) \[2\pi \sqrt{\frac{m\,\sin \theta }{2K}}\]
D) \[2\pi \sqrt{\frac{2m\,\sin \theta }{K}}\]
Correct Answer: A
Solution :
For mass m \[Kx+Kx=ma\] \[2Kx=ma\] \[{{K}_{eff}}=2K\] \[\therefore \] \[T=2\pi \,\sqrt{\frac{m}{2K}}\]You need to login to perform this action.
You will be redirected in
3 sec