A) \[\frac{\alpha }{1+\alpha }P\]
B) \[\frac{1-\alpha }{1+\alpha }P\]
C) \[P\alpha \]
D) none of these
Correct Answer: A
Solution :
\[\begin{align} & \underset{1-\alpha }{\mathop{\underset{\begin{smallmatrix} 1 \\ \end{smallmatrix}}{\mathop{PC{{l}_{5(g)}}}}\,}}\,\underset{\begin{smallmatrix} \\ \alpha \end{smallmatrix}}{\mathop{\underset{0}{\mathop{PC{{l}_{3(g)}}}}\,}}\,+\underset{\alpha }{\mathop{\underset{{}}{\mathop{\underset{0}{\mathop{C{{l}_{2\,(g)}}}}\,}}\,}}\,initial\,\,conc. \\ & at\,\,equilibrium \\ \end{align}\] Total number of mole at equilibrium \[=1-\alpha +\alpha +\alpha \] \[=1+\alpha \] Total pressure = P \[\because \] Partial pressure \[=\frac{mole\,\,fraction}{total\,pressure}\] \[\therefore \] Partial pressure of \[PC{{l}_{3}}=\frac{\alpha }{1+\alpha }P\]You need to login to perform this action.
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